20t^2+t-21=0

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Solution for 20t^2+t-21=0 equation:


Simplifying
20t2 + t + -21 = 0

Reorder the terms:
-21 + t + 20t2 = 0

Solving
-21 + t + 20t2 = 0

Solving for variable 't'.

Factor a trinomial.
(-21 + -20t)(1 + -1t) = 0

Subproblem 1

Set the factor '(-21 + -20t)' equal to zero and attempt to solve: Simplifying -21 + -20t = 0 Solving -21 + -20t = 0 Move all terms containing t to the left, all other terms to the right. Add '21' to each side of the equation. -21 + 21 + -20t = 0 + 21 Combine like terms: -21 + 21 = 0 0 + -20t = 0 + 21 -20t = 0 + 21 Combine like terms: 0 + 21 = 21 -20t = 21 Divide each side by '-20'. t = -1.05 Simplifying t = -1.05

Subproblem 2

Set the factor '(1 + -1t)' equal to zero and attempt to solve: Simplifying 1 + -1t = 0 Solving 1 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1t = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1t = 0 + -1 -1t = 0 + -1 Combine like terms: 0 + -1 = -1 -1t = -1 Divide each side by '-1'. t = 1 Simplifying t = 1

Solution

t = {-1.05, 1}

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